A cylinder of radius 12cm contains water upto the height of 20cm.A spherical iron ball is dropped into the cylinder and thus water level is raised by 6.75 cm.What is the radius of the ball ?
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Solution:-
Radius of the cylinder = 12 cm
Height of the cylinder = 6.75 cm
Let 'r' be the radius of the spherical iron ball.
Volume of the cylinder = volume of the spherical iron ball
πr²h = 4/3πr³
22/7*12*12*6.75 = 4/3*22/7*r³
3 × 12 × 12 × 6.75 = 4r³
2916 = 4r³
r³ = 2916/4
r³ = 729
r = 9 cm
So, the radius of the spherical iron ball is 9 cm.
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Answered by
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Step-by-step explanation:
volume of cylinder= V sphere
£R2 *3 = 4R3
by solving r 9
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