Math, asked by TbiaSupreme, 1 year ago

A cylinder of radius 2 cm and height 10 cm is melted into small spherical balls of diameter 1 cm. Find the number of such balls.

Answers

Answered by Amber2018
13

Volume of Cylinder V = π r^2 h

r= 2 cm, height = 10 cm

V = 125.7 cm^3 (approximate)

Volume of sphere V=4 /3πr^3

d = 1 cm, then r = 0.5 cm

V = 0.524 cm^3 (approximate)

Required no. of spherical balls =

 \frac{Volume of cylinder}{volume of spherical ball}

= 125.7/0.524

= 240

Answered by mysticd
6

Solution :


i ) dimensions of the cylinder:


Radius = R = 2 cm


Height = h = 10 cm


ii ) dimensions of the sphere:


Diameter ( d ) = 1 cm


Radius of each small sphere (r)


r = d/2 = 1/2 cm


NOW ,


If cylinder melted and cast


into small spheres ,


Let the number of spheres = n


n = ( volume of cylinder)/volume of each sphere )


n = ( πR²h )/[ (4/3)πr³ ]


=> n = (3 R²h )/( 4r³ )


=> n = ( 3×2×2×10)/[4×(1/2)³]


=> n = (3×10×2³)


=> n = 240


Therefore ,


Number bof small spheres = 240


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