A cylinder pillar is 1m in diameter and 4.2m In height. find the cost of white washing the curved surface of the pillar at the rate of rupees. 15 per m ^ 2
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4
D = 1m
R = 1/2= 0.5m
h=4.2
so c. s. a. of cylindrical pillar = 2πrh
= 2x 22/7x0.5x4.2
=13.2sq.m
now the rate of white washing=15sq.m
so 13.2x 15 =198Rs
R = 1/2= 0.5m
h=4.2
so c. s. a. of cylindrical pillar = 2πrh
= 2x 22/7x0.5x4.2
=13.2sq.m
now the rate of white washing=15sq.m
so 13.2x 15 =198Rs
Answered by
0
Answer:
r=0.5
h=4.2
csa=2×22/7×r×h
=2×22/7×0.5×4.2
=13.2
total cost=15× csa
=198
Step-by-step explanation:
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