A cylinder road roller is 2 metre long and 0.7 metre in diameter how much it will cover in 500 resolution
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maibhi same question per Atki hu
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Radius of a garden roller(r)=1.4/2=0.7 m
and length of the garden roller (h) = 2 m
∴ Curved surface area of garden roller = 2πrh .
So, the area levelled of a garden roller in one revolution is 8.8 m2.
Now, area levelled of a garden in 500 revolutions = 8.8 x 500= 4400m2.
Hope it will help u,if yes then plz mark it as brainliest...
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