the quadratic polynomial, the sum and the product of whose zeros are -1/4 and 1/4 respectively- (a)4x²-x+1(b)4x+x+1 (c)x²-4x+4(d)x²+4x-1
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2
Sum of zeroes, S = - 1/4
Product of zeroes, P = 1/4
The requires polynomial is –
f (x) = k [ x² - ( -1/4 )x + ( 1/4 ) ]
f (x) = k [ x² + 1/4 + 1/4 ]
f (x) = k [ ( 4x² + 1 + 1 ) / 4 ]
f (x) = k/4 ( 4x² + 1 + 1 )
Put k = 4
f (x) = 4x² + 1 + 1
is correct.
Product of zeroes, P = 1/4
The requires polynomial is –
f (x) = k [ x² - ( -1/4 )x + ( 1/4 ) ]
f (x) = k [ x² + 1/4 + 1/4 ]
f (x) = k [ ( 4x² + 1 + 1 ) / 4 ]
f (x) = k/4 ( 4x² + 1 + 1 )
Put k = 4
f (x) = 4x² + 1 + 1
is correct.
Answered by
0
Step-by-step explanation:
Let a and b its roots
a+b=−4 and ab=−1
∴ The equation is x
2
−(a+b)x+ab=0
⇒x
2
+4x−1=0
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