A cylinder roller is 2 meter in lengh with a radius of 50 cm . How many reovulations does it have to make to level an area of 528 m sq
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Radius =0.5m Length= 2m
Curved surface area of cylinder= 2πrh
= 2×3.14×0.5×2= 6.28m²
6.28m² area =1 revolution
528m² area = 528/6.28=84.07 revolution
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Curved surface area of cylinder= 2πrh
= 2×3.14×0.5×2= 6.28m²
6.28m² area =1 revolution
528m² area = 528/6.28=84.07 revolution
Hope u understand
Mark it as Brainliest
kokan6515:
Plz click red button n mark Brainliest too
Value of pie is 22/7 but u right 3.14 why
bhai π can be 22/7 n 3.14
Ok
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