Question

A right rectangular prism has a length of 5 cm, a width of 4 cm, and a height of 3 cm. The dimensions of the prism are doubled.
What is the surface area of the enlarged prism?

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___cm²

Answer 1

Given
Dimentions of the rectangular prism are
l=5cm, b=4cm, h=3cm
If each dimension is doubled then new prism dimensions are
L=10cm, B=8cm, H=6cm
Therefore Required surface area
Total surface area(TSA) =2(LB+BH+LH)
=2[10×8+8×6+10×6]
=2(80+48+60)
=2×188
=376square cm