A cylinder roller is 2m in length with a radius 50 cm how many revolution does it have to make to level an area of 528 m2
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Answered by
40
Here,
l/h=2m
r=50cm=50/100m=0.5m
CSA of cylinder =2πrh
=2*22/7*0.5*2
=44/7m
let, it revolve 'x' times to level 528m^2
so,
44/7*x=528
44x=528*7
x=528*7/44
x=48*7/4
x=84
so, the roller revolve 84 times to level 528m^2
l/h=2m
r=50cm=50/100m=0.5m
CSA of cylinder =2πrh
=2*22/7*0.5*2
=44/7m
let, it revolve 'x' times to level 528m^2
so,
44/7*x=528
44x=528*7
x=528*7/44
x=48*7/4
x=84
so, the roller revolve 84 times to level 528m^2
Answered by
3
thanks for the answer I also need the answer of this question
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