a cylinder tube open at both ends is made of iron 3 CM if the external diameter is 42 cm and the length of the tube is 140 cm find the volume of the metal used in it
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height of the tube=140 cm
external diameter=42cm
external radius (R) =42/2=21 cm
thickness=3cm
internal radius (r)= external radius - thickness
=21-3=18cm
volume = pie×R²×h - pie×r²×h
=pie×h(R²-r²)
=pie×h(R-r)(R+r)
=22/7×140(21-18)(21+18)
=22×20(3)(39)
=51480 cm³
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5
Answer:
51480cm^3
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