Question

A cylinder was filled with a gaseous mixture containing CO and N2 (equal masses). The ratio of their partial pressures in cylinder are

Answer 1

Let n1 and n2 be the moles of CO and N2 respectively.

Suppose there is x gram of CO and N2 in the cylinder as the masses are equal.

n1= x/28 and n2 = x/28 and n1+n2 = x/14

We know that P(CO) =X(CO) x P(total)
= n1/n1+n2 x P(total)
= 1/2 x P(total)
Similarly for P(N2) = 1/2 x P(total)

Therefore, P(CO)/P(N2) = 1.

This should be the answer I think. Please let me know if you find any mistake.

Answer 2

Question:

A cylinder was filled with gaseous mixture containing CO N2 (equal masses).The ratio of their partial pressure in cylinder are???

Solution:

Let the equal mass be x.

P(N2) / P(CO) = X(N2) / X(CO)

where, P = partial pressure , X = mole fraction.

and let n be number of moles,

n(N2) / n(CO) = x*28 / 28*x =  1

Hence, P (N2) = P(CO).

Since, partial pressure is equal, thereby, ratio is 1:1