Question

A cylinder with a movable piston contains 2.00 g of helium, he, at room temperature. More helium was added to the cylinder and the volume was adjusted so that the gas pressure remained the same. How many grams of helium were added to the cylinder if the volume was changed from 2.00 l to 3.50 l ? (the temperature was held constant.)

Answer 1

25-Mar-2014 · 2 answers

A cylinder with a movable piston contains 2.00g of helium, He, at room temperature. More helium was added to the cylinder and the volume was adjusted ...

2 votes

2g He = 2L. (2.9L / 2L) x 2g = 2.9g - 2g = 0.9g added. 

Answer 2

Heya....

Here's your answer.....

PV = nRT... R is a constant...

so PV/nT = constant...

P1V1 / n1T1 = P2V2 / n2T2...P is constant.T is constant.. so

V1 / n1 = V2 / n2

since n = mass / mw

V1 / (mass 1 / mw) = V2 / (mass 2 / mw)

and since molecular mass = constant

V1 / mass 1 = V2 / mass 2

mass 2 = V2 x mass 1 / V1 = 2.90L x 2.00 g / 2.00 L = 2.9 g

mass 2 - mass 1 = 2.90 g - 2.00 g = 0.90 g

ie.. 0.90 g of He was added.

Thanks...!!!

XD

Sorry baby 'wink'