A cylinderical mug of radius 5cm and height 9.8cm is full of water. A solid in the form of right circular cone mounted on a hemisphere is immersed into the mug. The radius of the hemisphere is 3.5cm and height of conical part 5cm . Find the volume of water left in the tub(take π=22/7).
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Answer:
Volume of water in tub=πr
2
h=π×5
2
×9.8cm
3
Volume of Hemishpere=
3
2
×π×3.5
3
cm
3
Volume of cone=
3
1
π×3.5
2
×5cm
3
Volume of water left in the tub = Volume of water in tub-Volume of toy
Volume left = π×25×9.8−(
3
2
×π×3.5
3
+
3
1
π×3.5
2
×5)
V=π(245−49)=
7
22
×196=22×28=616cm
Hope it will help you mate....
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