a cylindrical block of radius R and mass M is lying on the table if its radius is doubled and mass is tripled then what happened to the pressure acting on the table
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Pressure on table will be 3/4 times of original pressure.
Pressure is defined as "the force applied perpendicular to the surface of an object per unit area."
Formula to calculate pressure is given by -
P= F/A.
P= pressure, F= force, A= area
Force and area are calculated by given formula-
F= mg
A= 4πr²
M= mass, R= radius
According to given condition in question- r'= 2r and m'= 3m
P'= 3mg/4π(2r)²
P'= 3mg/4π4r²
P'= 3/4P
Hence, new pressure will be 3/4 times of original pressure.
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