A cylindrical body aa body weight of 16 N in a liquid whose sepecefic gravity is 6 . Find the weight of the body in water if it weighs 40 N in air
Answers
Answered by
0
Let W 1 , w2 , w3 be weight of the body in air , water and liquid , respectively .
W3 = 16 N ; w2 = X
W1 = 40 N
Specific gravity of the liquid = 6
W1-w3 / W1 - w2 =6
40-16/40-x = 6'
X= 36 N . Thus , weight of the body in water is 36 N .
Answered by
0
Answer:
aaaa
Explanation:
Similar questions