Math, asked by BrainlyHelper, 1 year ago

A cylindrical bucket, 32 cm high and 18 cm of radius of the base, is filled with sand. This bucket is emptied on the ground and a conical heap of sand is formed. If the height of the conical heap is 24 cm, find the radius and slant height of the heap.

Answers

Answered by nikitasingh79
74

Answer:

The radius and slant height of heap are 36 cm & 43.2 cm.

Step-by-step explanation:

Given :  

Height of a cylindrical bucket , H = 32 cm  

Radius of cylindrical bucket , R = 18 cm

Height of the conical heap of sand , h = 24 cm

Let the radius and slant height of the heap of sand be ‘r’  & ‘ l’.

Here, the sand filled in cylindrical bucket from a conical heap of sand on the ground. So volume of cylindrical bucket will be equal to the volume of conical heap.

Volume of cylindrical bucket = Volume of conical heap of sand  

πR²H = 1/3 πr²h  

R²H = 1/3 r²h  

18² × 32 = ⅓ × r² × 24

18 × 18 × 32 = 8r²  

r² = (18 × 18 × 32)/8

r² = 18 × 18 × 4

r² = 1296  

r = √1296

r = 36 cm

Radius of the heap of sand  = 36 cm

Slant height of the conical heap of sand, l = √(h² + r²  

l = √24² + 36² = √(576 + 1296) = √1872

l = √144 × 13 = 12√13  

l = 12√13 cm

l = 12 × 3.6 = 43.2 cm

slant height of the conical heap of sand, l = 43.2 cm

Hence the radius and slant height of heap are 36 cm & 12√13 cm .

HOPE THIS ANSWER WILL HELP YOU…..

Answered by BrainlyVirat
34

Step by step explanation :

Let the radius and slant height be r cm and L cm respectively.

Radius of the cylindrical bucket = 18 cm

Height of the cylindrical bucket=32 cm

Height of the conical heap =24 cm

The volume of sand remains the same in the bucket and in the heap.

So, Volume of cylindrical bucket = Volume of conical heap

\tt{\pi{r}^{2}h=\frac{1}{3}{\pi\:r}^{2}h}

\tt\small{\pi \times 18 { }^{2} \times 32 = \frac{1}{3} \pi \times r{}^{2}\times24}

\tt{{r}^{2}=\frac{3 \times 18\times 18 \times 32}{24}}

\tt{{r}^{2} =1296}

\tt{r = 36}

Now,

Slant height of the conical heap =

\tt{ \sqrt{r{}^{2}+h {}^{2} }}

\tt{ =\sqrt{36{}^{2} + 24 {}^{2} }}

\tt{=\sqrt{1296 + 576} }

\tt{ =\sqrt{1872}}

\tt{ = 43.25}

Thus, Slant height of the heap is 43.25 cm

Radius of the heap is 36 cm.

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