Question

A cylindrical bucket filled with 5 kg of water is whirled around in a vertical circular path of radius 1.8 m what should be the minimum speed at the top of path

Answer 1

For this you have to use the concept of rotational motion.

At the top of the path weight of bucket is balanced by centrifugal force. Hence

$\frac{m {v}^{2} }{r} = mg$

or

$v = \sqrt{rg}$

Putting value of r and g you will get v. I am assuming g = 9.8 m/s²

v = 4.2 m/s.

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Answer 2

Answer:

Yo yo

Explanation:

For this you have to use the concept of rotational motion.

At the top of the path weight of bucket is balanced by centrifugal force. Hence

\frac{m {v}^{2} }{r} = mgrmv2=mg

or

v = \sqrt{rg}v=rg

Putting value of r and g you will get v. I am assuming g = 9.8 m/s²

v = 4.2 m/s.

Please mark my answer Brainliest if it helps you.

Cheers ;)