Question

A Cylindrical can of internal diameter 21cm contains water. A solid sphere whose diameter is 10.5cm is lowered into the cylindrical can. The sphere is completely immersed in water. Calculate the rise in water level, assuming that no water overflows

Answer 1

SPHERE
Diameter = 10.5 cm.
Radius = 105/20
Volume = 4/3 π r³
4/3 × 22/7 × 105/20×105/20×105/20
= 11×105×105/10×20 cu.cm.
CYLINDER
Diameter = 21cm.
Radius = 21/2 cm.
Volume = πr²h
22/7× 21/2×21/2×h cu.cm
Volume of the cylinder= Volume of the sphere
22/7×21/2×21/2×h = 11×105×105/10×20
11×3/2×21×h = 11×105×105/10×20
h = 11×105×105×2/10×20×3×11×21
h= 1.75

Answer 2

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