Question

a cylindrical can whose Base is horizontally and radius 3.5 cm contains sufficient water so that when a sphere is placed in the can ,the water just covers the sphere . given that the sphere just fits into the can, calculate:1) total surface area of the can in contact with water when the sphere is in it. 2) the depth of water in the can before the sphere was put into it.

Answer 1

with the area u can easily find the height which will be the depth using r=3.5 cm

Answer 2

Answer:

here was the part one of the answer and the second is :

ANSWER

ii)

Depth of water in the can before sphere is put inside it

                

                   =volume of water/area of cross section of can

                 =(2/3 *πR³)/πR²

=2/3 *R

=2/3 *3.5

=7/3 cm

hope this helps

hope this helps please mark me as a brainlist

hope this helps please mark me as a brainlist thanks to you