If the average of 10 numbers is 12 and the average of first 7 numbers is 7 then find the average of last 3 numbers
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The average of the 10 numbers is 12
Therefore the sum of the 10 numbers is 10×12 or 120
Then the question says that the average of first 7 numbers is 7
Therefore the sum of the 7 numbers is 7×7 or 49
The sum of the remaining 3 numbers is 120-49 or 71
Therefore the average of the 3 numbers is 71÷3 or 23.667
Therefore the sum of the 10 numbers is 10×12 or 120
Then the question says that the average of first 7 numbers is 7
Therefore the sum of the 7 numbers is 7×7 or 49
The sum of the remaining 3 numbers is 120-49 or 71
Therefore the average of the 3 numbers is 71÷3 or 23.667
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