A cylindrical conductor of length ‘l and uniform area of cross-section 'A'
has resistance 'R'. Another conductor of length 2.5 l and resistance 0-5 R
of the same material has area of cross-section
(A)
5 A
2.5 A
(C) 0.5 A
(D) LA
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R = ρL/A
R₁/R₂ = (L₁/L₂) × (A₂/A₁)
A₂ = (R₁/R₂) × (L₂/L₁) × A₁
A₂ = (R/R) × (2L/L) × A
A₂ = 2A
Cross section area of another conductor is 2A
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