Question

A cylindrical conductor of length 'l' and uniform area of cross-section 'A' has resistance 'R'. Another conductor of length 2.5 'l' and resistance 0.5 'R'
of the same material has area of cross-
(A) 5 A
(B) 2.5 A
(C) 0.5 A
(D) 1/5 A​

Answer 1

Answer:c

Fire

Explanation:

Answer 2

Area of second resistance = 5 × Area of 1st conductor

Given:

• A cylindrical conductor of length 'l' and uniform area of cross-section 'A'.
• Resistance 'R'.
• Another conductor of length 2.5 'l' and resistance 0.5 'R'.
• Same material.

To find:

       Area of cross section of second conductor.

Formula used:

R ∝ $\frac{L}{A}$

Where, R =  Resistance

            L = Length of conductor

            A = Area of conductor

Explanation:

R ∝ $\frac{L}{A}$  ⇒ A∝ $\frac{L}{R}$

For second conductor L =  Length of conductor= 2.5 'l'

                                      R = Resistance =  0.5 'R'.

A∝ $\frac{L}{R}$ ⇒  A∝ $\frac{2.5l}{0.5R}$ ⇒ A∝ 5 ×$\frac{l}{R}$

So the area of second resistance = 5 × area of 1st conductor.

To learn more....

1 A 3V battery of internal resistance 1 ohm is joined to a sliding wire of length 100cm and resistance 5 ohm. A voltmeter, which takes negligible current, is connected across 60cm length of the wire. What is the reading of the voltmeter? if the resistance of the voltmeter were 150 ohm then what would have been its reading?

https://brainly.in/question/10568489

2 The resistance offered by each bulb of the fairy light is 20 ohm .calculate

1) the total resistance due to 5 such bulbs of fairy light

2) if the potential difference of 50v is applied to its terminal,calculate the current flowing through it.

3) what would happen if one of the bulbs got fused or turned dead ? also state what need to be done in this

https://brainly.in/question/3993724