Question

A cylindrical conductor of length l' and uniform area of cross-section 'A'
has resistance 'R. Another conductor of length 2.5 l and resistance 0-5 R
of the same material has area of cross-section
(A) 5A
(B) 2.5 A
0-5 A
(D) A​

Answer 1

Explanation:

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Answer 2

The cross sectional area of another conductor is 5A.

Explanation:

The resistance is given by the formula:

R = ρL/A

The resistance of one conductor is:

R₁ = ρL₁/A₁

Where,

R₁ = R

L₁ = L

A₁ = A

Now, the resistance is:

R = ρL/A

A = ρL/R → (equation 1)

The resistance of another conductor is:

R₂ = ρL₂/A₂

Where,

R₂ = 0.5 R

L₂ = 2.5 L

A₂ = ?

Now, the resistance is:

0.5 × R = (ρ × 2.5 × L)/A₂

A₂ = (ρ × 2.5 × L)/(0.5 × R)

A₂ = 5 × ρL/R

On substituting equation (1), we get,

∴ A₂ = 5A