Question

A cylindrical conductor of length L and uniform area of cross sectional A has resistance R. another conductor of length 2.5 L and resistance 0.5 R of the same material has area of cross section​.

Answer 1

Answer:

U continue with the formula of R=pl/a

answer is 5 A

Answer 2

fir the 1st conductor,

$p = r \frac{a}{l}$

for the 2nd conductor,

$p = 0.5r \times \frac{a2}{2.5l} = 0.2 \times r \frac{a2}{l}$

here, same conductors were used in both cases,

so,

$r \frac{a}{l} =0.2 \times r \frac{a2}{l} \\ > a = 0.2 \times a2$

note: consider '2' of a2 as a subscript