Question

A cylindrical container base radius 8cm and height 42 cm find the curved surface area and total surface area of the cylinder

Answer 1

your answer is here.

Answer 2

$\large\underline\pink{Given:-}$

• A cylindrical container base radius 8cm and height 42cm.

$\large\underline\pink{To find:-}$

• Fine the CSA and TSA of the cylinder ....?

$\large\underline\pink{Solutions:-}$

Curved surface area of Cylinder = 2πrh

$\: \: \: \: \: \leadsto \: \: {2} \: \times \: \frac{22}{7} \: \times \: {8} \: \times \: {42}$

$\: \: \: \: \: \leadsto \: \: {44} \: \times \: {8} \: \times \: {6}$

$\: \: \: \: \: \leadsto \: \: {44} \: \times \: {42}$

$\: \: \: \: \: \leadsto \: \: {2112} \: {cm}^{2}$

Total surface area = 2πr(h + r)

$\: \: \: \: \: \leadsto \: \: {2} \: \times \: \frac{22}{7} \: \times \: {8} \: {({42} \: + \: {8})}$

$\: \: \: \: \: \leadsto \: \: {2} \: \times \: \frac{22}{7} \: \times \: {8} \: \times \: {50}$

$\: \: \: \: \: \leadsto \: \: \frac{{44} \: \times \: {400}}{7}$

$\: \: \: \: \: \leadsto \: \: \frac{17600}{7}$

$\: \: \: \: \: \leadsto \: \: {2514.28} \: {cm}^{2}$

Hence, the CSA and TSA of the cylinder is 2112 cm² and 2514.28 cm²

$\large\underline\pink{More \: Important:-}$

• Volume of cylinder ( Area of base × height ).

= (πr²) × h

= πr²h

• Curved surface = ( Perimeter of base ) × height.

= (2πr) × h

= 2πrh

• Total surface are = Area of circular ends + curved surface area.

= 2πr² + 2πrh

= 2πr(r + h)

Where, r = radius of the circular base of the cylinder.

h = height of cylinder.