Question

A cylindrical container has a base area of 150 cm2 and is filled with water to a depth of 25 cm. Find the pressure due to water on the base

a)Calculate the mass of water in the cylinder (density=1000 kg/m3)

b) calculate the pressure exerted by the water at the base of the cylinder *

Answer 1

Answer:

a]Pressure = hdg= 0.06 m × 10³ kg/m³ × 10 m/s² = 600 PaPressure ... 1000 kg m^-3 is poured into up to a depth of 6 CM calculate ... (b) the trust of water on the base is equals to 10 ns ...

Answer 2

Answer:

The mass of water in the cylinder is 3.75 kg and the pressure exerted by the water at the base of the cylinder is 2500 pascal.

Explanation:

The values given in the question are,

Area=150cm²=0.015m²

Depth=25cm=0.25m

Pressure is given as,

$P=\rho gh$       (1)

Where,

P= pressure

ρ=density

g=acceleration due to gravity=10 ms⁻² (constant)

$P=1000\times 10 \times 0.25=2500 pascal$

(a) To find mass we first need to know the relation between mass volume and density i.e.

$\rho=\frac{m}{volume}$                    (2)

$mass=\rho \times volume$        (3)

For volume, we know,

$Volume=Area\times height$    (4)

$Volume=0.015\times0.25=0.00375$

By substituting the value of volume and density in equation (2) we get;

$mass=1000\times 0.00375=3.75kg$

(c)

The pressure exerted by water at the base of the cylinder is given as,

$P=\rho gh$

$P=1000\times 10 \times 0.25=2500 pascal$

Hence, the mass of water in the cylinder is 3.75 kg and the pressure exerted by the water at the base of the cylinder is 2500 pascal.