a cylindrical container of radius r and height h is completely filled with a liquid. two horizontal l shaped pipes of small cross sectional area a are connected to the cylinder. now the two pipes are opened and fluid starts flowing out of the pipe horizontally in opposite direction. than the torque due to eject liquid on the system is
Answers
The torque due to eject liquid will be 2arρgh
Explanation :
The pressure exerted at the bottom of the container, P = ρgh
where ρ = density of the liquid
g = acceleration due to gravity
h = height where the pipes are connected( at the bottom)
given the area of cross section = a
Hence force exerted by the liquid F = P x a = ρgha
Diameter of the container = d = 2r
We know that torque T = F x d
=> T = ρgha x 2r = 2arρgh
Hence the torque due to eject liquid will be 2arρgh
Answer:
4arρgh
Explanation:
The pressure exerted at the bottom of the container, P = ρgh
where ρ = density of the liquid
g = acceleration due to gravity
h = height where the pipes are connected( at the bottom)
given the area of cross section = a
Hence force exerted by the liquid F = P x a = ρgha
Diameter of the container = d = 2r
We know that torque T = F x d
=> T1 = ρgha x 2r = 2arρgh T2=ρgha x 2r = 2arρgh
now as there are two pipes we will have net torque T=T1+T2=4arρgh
Hence the torque due to eject liquid will be 4arρgh