Question

A cylindrical drum has a radius of 0.45 m and is initially at rest. It is then given an angular acceleration of 0.40 rad s−2. At time t = 8.0 s calculate (i) the angular speed of the drum, (ii) the centripetal acceleration of a point on the rim of the drum, (iii) the tangential acceleration at that point, and (iv) the resultant acceleration at that point.

Answer 1

Resistance of a metal wire of length 2m is 14 ohm at 20 degree Celsius if the diameter of the wire is 0.6 millimetre what will be the resistivity of the metal at that temperature

Answer 2

Hello buddy,

● Answer -
1) ω = 3.2 rad/s
2) ac = 4.608 m/s^2
3) at = 0.18 m/s^2
4) a = 4.611 m/s^2

● Explanation -
# Given -
r = 0.45 m
α = 0.4 rad/s^2
t = 8 s

# Solution -
1) Angular speed of drum -
ω = αt
ω = 0.4 × 8
ω = 3.2 rad/s

2) Centripetal acceleration -
ac = rω^2
ac = 0.45 × 3.2^2
ac = 4.608 m/s^2

3) Tangential acceleration -
at = rα
at = 0.45 × 0.4
at = 0.18 m/s^2

4) Resultant acceleration -
a = √(ac^2 + at^2)
a = √(4.608^2 + 0.18^2)
a = 4.611 m/s^2

Hope this helped....