Question

a cylindrical iron pipe has an outer diameter of 28 cm and inner diameter of 14 cm. its length is 1 m. find the cost of painting is at 10rs per cube cm.

Answer 1

hHeya...☺☺✌
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volume of cylinder =
$\pi \: rh {}^{2}$
Outer radius = 14 cm
Inner radius = 7 cm
Height = 1 cm

With the formula => pi ( R^2 - r^2 ) × h

The volume will be 462

For cost of painting 462×10 = 4620

Thanks..☺☺

Answer 2

Given,

Outer Diameter = 28 cm
Outer radius (R) = 28/2 cm = 14 cm

Similarly,

Inner radius (r) = 7 cm

Height = 1 m = 100 cm

=> Volume = π (R^2 - r^2) x h

=> V = 22/7 {(14)^2 - (7)^2} x 100

=> V = 22/7 x ( 196 - 49) x 100

=> V = (22/7 x 147 x 100) cm^3

=> V = 46200 cm^3


Now,

=> Cost = Rs ( 46200 x 10)

=> Cost = Rs 462000




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