a particle starts moving with acceleration 2m/s . The distance travelled by it in the 5th half second is?
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we have to find distance in 5th half second.
Formula: s=ut+(1/2)a(t^2)
t^2 = (5/2)^2 – (2)^2 = 2.25 and using this in our formula distance travelled is: 2.25m
Formula: s=ut+(1/2)a(t^2)
t^2 = (5/2)^2 – (2)^2 = 2.25 and using this in our formula distance travelled is: 2.25m
meera08418:
why do we take the difference of 5/2 and 2 secs?
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