A cylindrical metal pipe is 14 cm long. The difference between the outside and inside surfaces is 44cmsq. If the pipe is made up of 99 cm cube of metal, find the outer and inner radii of the pipe.
Answers
Answered by
4
let r1 be radius of outer and r2 be radius of inner
2pie h( r1 -r2) = 44
28 pie ( r1-r2) = 44
r1 -r2 = 44/28 .pie = 11/7 .pie
pie h ( r1^2 - r2 ^2) = 99
r1 ^2 - r2 ^2 = 99/14. pie
(r1-r2)(r1+r2) = 99/14 .pie.
r1+ r2 = 99/14.pie .7/ (11 pie)
= 9/2
r1 - r2 = 11/7 PIE
2r1 = 9/2 + 11/7 pie
r1 = 9/4 + 11/14 pie
2pie h( r1 -r2) = 44
28 pie ( r1-r2) = 44
r1 -r2 = 44/28 .pie = 11/7 .pie
pie h ( r1^2 - r2 ^2) = 99
r1 ^2 - r2 ^2 = 99/14. pie
(r1-r2)(r1+r2) = 99/14 .pie.
r1+ r2 = 99/14.pie .7/ (11 pie)
= 9/2
r1 - r2 = 11/7 PIE
2r1 = 9/2 + 11/7 pie
r1 = 9/4 + 11/14 pie
Similar questions