Question

a cylindrical milk Storage tank has 4.2 metre as diameter and 4.5 metres height how much Steel sheet was actually used to make this closed tank if 1 by 7 of Steel sheet was wasted making the tank​

Answer 1

Answer:

t.s.a=2 \pir r(r+h)

22/7*2*2.1(2.1+4.5)+1/7(2*22/7*2.1(2.1+4.5)=87.12+12.4457=99.5657m2

Answer 2

Question =》

a cylindrical milk Storage tank has 4.2 metre as diameter and 4.5 metres height how much Steel sheet was actually used to make this closed tank if 1 by 7 of Steel sheet was wasted making the tank

Given =》

Cylindrical milk steel storage tank has 4.2 m as diameter and 4.5m height

Solution =》

a) quantity of milk it can contain = Volume of cylindrical milk steel storage tank

We know volume of cylinder =

$2\pi \: rh$

so,

Volume of cylindrical milk steel storage tank =

$2 \times \frac{22}{7} \times 2.1 {}^{2} \times 4.5 \\ \\ = 62.37m {}^{3}$

We know 1³=1000 L

Quantity of milk it can contain = 62.37m³= 62370 L

B) Steel sheet was actually used to make this closed tank , if 1/7 of steel sheet was wasted in making the tank .

so,

Total steel sheet = Total surface area of tank ( As we have closed tank ) +1/7Total surface area of tank

We know that total surface area of cylinder =

$2\pi \: r(h + r)$

Total sheet =

$2 \times \frac{22}{7} \times 2.1(2.1 + 4.5) + \frac{1}{7} (2 \times \frac{22}{7 } \times 2.1(2.1 + 4.5)) \\ = 2 \times 22 \times 0.3 \times 6.6 + \frac{1}{7} (2 \times 22 \times 0.3 \times 6.6) \\ = 87.12 + \frac{1}{7} \times 87.12 \\ = 87.12 + 12.4457 \\ = 99.5657 \\ = 99.57m {}^{2}$

Hope this information will clear your doubts about topic

: )