Question

A cylindrical road roller is 3 m long and its diameter is 49 m find the area of covered by it in 200 revolution

Answer 1

D=49m

r=49/2m

curved surface area =2Πrh

=2*22/7*49/2*3

=462m²

1 revolution=462m²

200 revolution=462*200

=92,400m²

Answer 2

The area covered of 200 revolution is 184724 m².

Step-by-step explanation:

Given that,

Length of cylindrical road roller= 3 m

Diameter of cylindrical road roller= 49 m

Revolution = 200

We need to calculate the area of covered surface

Using formula of area

$A=2\pi\times r \times h$

Where, r = radius

h = height

Put the value in to the formula

$A=2\times\pi\times49\times3$

$A=923.62\ m^2$

So, Area of 1 revolution  = 923.62 m²

Area of 200 revolution = 200\times923.62[/tex]

Area of 200 revolution = 184724 m²

Hence, The area covered of 200 revolution is 184724 m².

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Topic : Area

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