A cylindrical road roller is of length 2 metre and diameter 84 cm. find the number of revolution it has to make to cover an area of 7920 m².
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Answer: Hi........hope that the answer helps : )
Step-by-step explanation:
CSA = PIE × r × h = 22÷7 × .42 × 2 = 22 × .6 × 2 = 26.4 m ^ 2
No of revolutions = 7920 ÷ 26.4 = 300
Thanks
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