Question

a cylindrical rod iron whose height is 4 times its radius is melted and cast into spherical balls of the same radius the number of balls castries

Answer 1

Hlw mate!!

Let the number of balls be n. Given that cylindrical rod whose height is 8 times of its radius i.e. h = 8r. Volume of cylinder = n x Volume of sphere. πr2h = n x (4/3)πr3πr2x 8r = n x (4/3)πr3 n = 8πr3 / (4/3)πr3 n = 24 / 4 = 6 ∴ Number of balls = 6.


Hope it helpful

Answer 2

The number of balls castries is 3

Step-by-step explanation:

Let the radius of cylindrical rod be r

We are given that a cylindrical rod iron whose height is 4 times its radius is melted and cast into spherical balls of the same radius

So, Height of cylindrical rod = 4r

Volume of cylindrical rod =$\pi r^2h = \pi r^2(4r)$

Volume of spherical ball =$\frac{4}{3} \pi r^3$

No. of balls formed = $\frac{\pi 4r^3}{\frac{4}{3} \pi r^3}=3$

Hence  the number of balls castries is 3

#Learn more:

Cylindrical rod height 8 times of its radiusis melted and recast into spherical baolls of same radius find number of bolls

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