A wooden rectangular plank has dimensions 12m and 6 m. Three circular portions are cut from the plank having diameters 2m, 2m and 1m.How much area of the plank remains?
Answers
Answered by
2
given the dimensions of the rectangular plank = 12m × 6m
area of the rectangular plank = 12 × 6
= 72m²
now, we have to find the left of remaining area of the rectangular plank after cutting three circular portions of diameter 2m, 2m and 1m.
area of the circle having diameters 2m = 2(πr²)
= 2(22/7 × 2/2 × 2/2)
= 2 × 22/7
= 44/7cm²
area of the circle having diameter 1m = πr²
= 22/7 × 1/2 × 1/2
= 11/7 × 1/2
= 5.5/7cm²
total area of these circular portions = 44/7 + 44/7 + 5.5/7
= 93.5/7cm²
therefore area of remaining plank = 72 - 93.5/7
= (72×7)/7 - 93.5/7
= (504 - 93.5)/7
= 410.5/7
= 58.64cm² (approximately)
Answered by
0
Answer:
area of rectangle = length×
breadth(l×b)
area of circle = πr2
area of remaining =12×6-[2(π×1×1) + (π×1/2 × 1/2)]
remaining area :2-(2π+π/4) 72 - 9π/4
=(288-9π)/4 sq.m
Similar questions