Question

A cylindrical roller 2.5 m in length 1.75 in radius when road on a road was found to cover the area 500 5500 m square how many revolution did it make

Answer 1

Hi there !!

The length of the cylindrical pipe is the same as its height.

h = 2.5 m

r = 1.75 m

Total area covered = 5500 m²

Area covered by 1 revolution = C.S.A of the pipe

= 2πrh

= 2 × 22/7 × 1.75 × 2.5

= 27.5 m²

No : of revolutions made = Total area covered ÷ C.S.A

= 5500 ÷ 27.5

= 200 revolutions