A cylindrical roller 2.5 m in length 1.75 in radius when road on a road was found to cover the area 500 5500 m square how many revolution did it make
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Hi there !!
The length of the cylindrical pipe is the same as its height.
h = 2.5 m
r = 1.75 m
Total area covered = 5500 m²
Area covered by 1 revolution = C.S.A of the pipe
= 2πrh
= 2 × 22/7 × 1.75 × 2.5
= 27.5 m²
No : of revolutions made = Total area covered ÷ C.S.A
= 5500 ÷ 27.5
= 200 revolutions
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