a cylindrical roller 2.5 m in length and 1.75m in radius when roled on a road was found to cover an area of 5500m2.How many revolutions did it make
Answers
Answered by
5
curved surface area = 2 × 22 / 7 × 2.5×1.75=27.5m^2
Area covered = 5500m^2
No.of the revolutions=5500/27.5=200 revolutions
Hope it helps!
Thankyou
☆ ☆
Bebrainly
Area covered = 5500m^2
No.of the revolutions=5500/27.5=200 revolutions
Hope it helps!
Thankyou
☆ ☆
Bebrainly
Answered by
4
here csa of the roller => 2*22/7*1.75*2.5
=> 27.5m^2
area => 5500m2
number of rotations => 5500/27.5=> 200
=> 27.5m^2
area => 5500m2
number of rotations => 5500/27.5=> 200
Similar questions