a cylindrical roller is of length 2m and diameter 1.4m find the area it will level in 2500 revolutions.
Answers
Answered by
0
Circumference= pi*d
C=22/7*1.4
=4.4m
area leveled= 2500*4.4
=11000m^2
C=22/7*1.4
=4.4m
area leveled= 2500*4.4
=11000m^2
Answered by
4
hope my answer would help you
Attachments:
Similar questions