Math, asked by ggmonsterhallows, 1 year ago

a cylindrical roller is of length 2m and diameter 84cm. find the area covered by it in 300 revolutions

Answers

Answered by avinashsingh48
10
h = 2 m
d = 84 cm = 0.84 m
r = 0.42 m

Curved surface area = 2πrh
= 2 × 22/7 × 42/100 × 2
= 5.28 sq. m

Revolutions made = 7920/5.28 = 1500

Hope this helps!!!
Plsss make it the brainliest!!!

ggmonsterhallows: Sorry
ggmonsterhallows: Diameter is 42
ggmonsterhallows: Radius is 42 sorry
ggmonsterhallows: Length 200
ggmonsterhallows: U r reported b I t c h
gepadm: after 300 revolution area will remain same as one
ggmonsterhallows: U r d umber than the other one
ggmonsterhallows: #d u m b a s s
Answered by Anonymous
1

Answer:

1584 m²

Step-by-step explanation:

Length = 2 m.

Diameter = 84 cm = 0.84 m

Radius = 0.84/2

            = 0.42 m


Area covered by the roller in one revolution = 2πrh

= 2 * (22/7) * 0.42 * 2

= 5.28 m²


Area covered by the roller in 300 revolutions = 300 * 5.28

= 1584 m²


Therefore, Area covered in 300 revolutions = 1584 m²


Hope it helps you

#Bebrainly

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