Question

A cylindrical specimen of copper having an original diameter of 15.2mm is pulled in tension with 9,500 N force, producing only elastic deformation.what is the resulting engineering stress in the specimen?​

Answer 1

Actually, I have no idea what I am doing but still.....

Given data Suggests that

D = 15.2mm = 0.0152 m

T=F= 9500 N

And,

Stress = F/A

A= 2πrh Cylinder

Stress = 9500/2πrh

I really have no idea here, as the height is unknown or not in the question,But still...

Stress = 9500/2*3.14*0.076*h

--> Stress= 1133.54*h

Thats what I know...

Hope is simplifies upto some extent... Thanks!!