Question

a cylindrical tank has a capacitu of 6160find its depth if its radius id 14 m calculate the cost of painting its curved surface (outer) at the rate of ₹ 3/ m 2​

Answer 1

Answer:

volume of cylindrical tank=πr square ×h

6160=22/7×14×14×h

6160=28×22×h

6160=616h

6160÷616=h

h=10m ans

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Answer 2

Answer:

$volume \: of \: cylinder \: = \: 6160 {m}^{3} \\ radius \: of \: cylinder \: = \: 14m \\ \pi {r}^{2}h \: = \: 6160 \\ \frac{22}{7} \times 14 \times 14 \times h = 6160 \\ 22 \times 2 \times 14 \times h = 6160 \\ 44 \times 14 \times h = 6160 \\ 616 \times h = 6160 \\ h = \frac{6160}{616} \\ h = 10m \\ now \\ c.s.a \: of \: cylinder \: = \: 2\pi rh \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \: 2 \times \frac{22}{7} \times 14 \times 10 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \: 44 \times 2 \times 10 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \: 880 {m}^{2} \\ rate \: of \: painting \: 1 {m}^{2} = 3rs \\ cost \: of \: painting \: 880 {m}^{2} = 880 \times 3 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \: 2640rs \\ \\ \\ hope \: it \: helps.............. \\ plz \: mark \: as \: branliest................$