Question

A cylindrical tank has a capacity of 5632 m cube. If the diameter of its base is 16 cm. Find its depth.

Answer 1

Diameter(d) = 16 m

radiu(r) = 8 m

Height = H

volumeof the cylindrical tank = 5632 m³

volumeof the cylinder = πr²h

∴πr2h = 5632 (22/7) x 8 x 8 x h

=> 5632 h = (5632 x 7) / ( 22 x 8 x 8)

h = 28 m

Answer 2

Answer:

DEPTH = 28m

Step-by-step explanation:

$\begin{gathered}\begin{gathered}\pink{ \frak{Given}} \begin{cases} \sf \: Diameter\:= 16 \: cm \\ Base \: = \: half \: of \: diameter \: = 8cm \: cm \sf \end{cases} \\ \\\end{gathered}\end{gathered}$

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Formula used :

$\begin{gathered}\begin{gathered}: \implies \underline{ \boxed{\displaystyle \sf \bold{\:Volume \: of \: cylinder \: = \: \pi {r}^{2} h }} }\\ \\\end{gathered}\end{gathered}$

$\begin{gathered}\begin{gathered}\\ : \implies \displaystyle \sf \: 5632 {m}^{3} \: = \frac{22}{7} \: \times( 8) ^{2} \: \times \: h \\ \\ \\\end{gathered}\end{gathered}$

$\begin{gathered}\begin{gathered}\\ : \implies \displaystyle \sf \: 5632 {m}^{3} \: = \frac{22}{7} \: \times\: 8 \: × \: 8\: \times \: h \\ \\ \\\end{gathered}\end{gathered}$

$\begin{gathered}\begin{gathered}\\ : \implies \displaystyle \sf \: \frac{ 5632 \times \: 7 }{ 22 \: \times \: 8 \: \times 8 \: } = \: h \\ \\ \\\end{gathered}\end{gathered}$

$\begin{gathered}\begin{gathered}: \implies \underline{ \boxed{\displaystyle \sf \bold{\: 28m \: = \: Height / \: Depth}} }\\ \\\end{gathered}\end{gathered}$

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