Question

a cylindrical tank has a capacity of 5632 m square to metre square point if the diameter of its base is 16 metre find its depth​

Answer 1

Answer:

Answer:

Given:-

Diameter of cylinder tank = 16m

Volume of cylinder tank = 5632 m²

Find:-

Depth of cylinder tank???

Solution:-

Radius = Diameter /2

Radius = 16/2 = 8

So, Radius of cylinder tank is 8m

We know that ⤵

${ \boxed{ \sf{Volume = \pi \: {r}^{2} h}}}$

${ \to{5632 = \frac{22}{7} \times {8}^{2} \times h}}$

${ \to{5632 = \frac{22}{7} \times 64 \times h}}$

${ \to{ \frac{5632}{64} = \frac{22}{7} \times h }}$

${ \to{88 = \frac{22}{7} \times h}}$

${ \to{88 \times \frac{7}{22} = h }}$

$\to \: h = \frac{616}{22}$

$\to{h = 28}$

Therefore, height (depth) of cylinder is 28m

Step-by-step explanation:

Verification:-

Volume of cylinder = πr²h

5632 = 22/7 × 8² × 28

5632 = 22/7 × 64 × 28

5632 = 22/7 × 1792

5632 = 39424/7

5632 = 5634

Hence, proved ✔

Answer 2

S O L U T I O N :

$\underline{\bf{Given\::}}$

• Capacity of a cylindrical tank, (V) = 5632 m²
• Diameter of it's base, (D) = 16 m

$\underline{\bf{Explanation\::}}$

As we know that formula of the volume of cylinder;

$\boxed{\bf{Volume = \pi r^{2} h \:\:(cubic\:unit)}}$

A/q

• Radius = Diameter/2
• Radius = 16/2
• Radius = 8 m

Now,

$\longrightarrow\tt{Volume\:_{(cylindrical\:tank)}= \pi r^{2} h}$

$\longrightarrow\tt{5632= 22/7 \times (8)^{2} \times h}$

$\longrightarrow\tt{5632= 22/7 \times 8 \times 8 \times h}$

$\longrightarrow\tt{5632= 22/7 \times 64 \times h}$

$\longrightarrow\tt{\cancel{5632}= 22/7 \times \cancel{64} \times h}$

$\longrightarrow\tt{88= 22/7 \times h}$

$\longrightarrow\tt{88= 22h/7}$

$\longrightarrow\tt{88 \times 7 = 22 h}$

$\longrightarrow\tt{616 = 22 h}$

$\longrightarrow\tt{h = \cancel{616/22}}$

$\longrightarrow\bf{h = 28\:m}$

Thus,

The depth of the cylindrical tank will be 28 m .