A cylindrical tank has a capacity of 6160 m3. Find the depth, if it's radius is 14m. Also find the cost of painting it's curved surface at rupees 30 per metre 2.
Answers
Answer:
Given radius of cylindrical tank = 14 m
• Given capacity of a cylindrical tank = 6160 m³
We know that capacity = volume
• So, given volume of the cylindrical tank = 6160 m³
• But, volume of any cylinder = πr²h, where π (pi) = 22/7, r is the radius of the cylinder and h is the height/depth of the cylinder.
=> πr²h = 6160
=> 22/7 × (14)² × h = 6160
=> 22/7 × 196 × h = 6160
=> 22 × 28 × h = 6160
=> 616 × h = 6160
=> h = 6160/616
=> h = 10 m
• So, depth of the cylindrical tank = 10 m
• Now, Curved surface area (C.S.A) of the tank
= 2πrh
= 2 × 22/7 × 14 × 10
= 2 × 22 × 2 × 10
= 880 m²
• Now, cost of painting 1 m² = 30 Rs.
• So, cost of painting 880 m²
= 880 × 30
= 26400 Rs.
• Therefore, cost of painting the C.S.A of the cylindrical tank = 26,400 Rs.
Step-by-step explanation:
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Answer:
Depth of cylinder= 10m
Cost of painting the cylinder= 63360₹
Step-by-step explanation:
Capacity= volume
Volume of cylinder= 6160m³= πr²h
πr²h=6160
(22/7)(14)(14)(h)=6160
(22)(2)(14)(h)=6160
(44)(14)(h)=6160
h=6160/(44)(14)
h= 6160/616
h= 10m
Cost of painting=30₹/m²
TSA of cylinder= 2πr(r+h)
=2(22/7)(14){14+10}
=(2)(22)(2){24}
= (4)(22)(24)
= (88)(24)
= 2112m²
Cost of painting the cylinder= (TSA of cylinder)(cost of painting)
=> (2112m²)(30₹)
=> 63360₹
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