Physics, asked by ridhibhugra, 4 months ago

A cylindrical tank of base area 500 cm? has a small hole of area 10cmt near the
bottom. Water starts pouring on it a rate of 1000 cm/sec, at the same time it is
draining out through the hole. The maximum height of water in the tank will be (g=10
m/s2
(A) 5cm
(B) 10cm
(C) 2.5 cm
(D) 2cm​

Answers

Answered by aviy9133
2

Answer:

5cm........................

Answered by dreamrob
0

Given :

A = 500cm

a = 10cm

∝ = 1000cm³/sec

g = 10m/s²

To find :

Maximum height of water in the tank.

Solution :

v = √2gh

∝ = av

∝ = a√2gh

∝² = a²(2gh)

h = ∝² / 2ga²

h = (1000 × 1000) / (2 × 10 × 10² × 10 × 10)

h = 5cm

Therefore, maximum height of water in the tank is 5cm.

Similar questions