A cylindrical tank of base area 500 cm? has a small hole of area 10cmt near the
bottom. Water starts pouring on it a rate of 1000 cm/sec, at the same time it is
draining out through the hole. The maximum height of water in the tank will be (g=10
m/s2
(A) 5cm
(B) 10cm
(C) 2.5 cm
(D) 2cm
Answers
Answered by
2
Answer:
5cm........................
Answered by
0
Given :
A = 500cm
a = 10cm
∝ = 1000cm³/sec
g = 10m/s²
To find :
Maximum height of water in the tank.
Solution :
v = √2gh
∝ = av
∝ = a√2gh
∝² = a²(2gh)
h = ∝² / 2ga²
h = (1000 × 1000) / (2 × 10 × 10² × 10 × 10)
h = 5cm
Therefore, maximum height of water in the tank is 5cm.
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