A cylindrical tub of radius 12 cm contains water to a depth of 20cm.A spherical ball is dropped and thus the level of water is raised by 6.75cm.Wat is the radius of the ball
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HEY......
HERE IS UR ANSWER......
LET r RADIUS OF CYLINDER
LET r1 BE RADIUS OF BALL
h = 6.5cm
FROM ARCHEMEDIS' PRINCIPLE
4/3πr1(cube) = πr(square)h
SO, r1(cube) = 12×12×6.75×3/4
SO, r1(cube) = 729
THEREFORE , RADIUS OF BALL = 9cm
HERE IS UR ANSWER......
LET r RADIUS OF CYLINDER
LET r1 BE RADIUS OF BALL
h = 6.5cm
FROM ARCHEMEDIS' PRINCIPLE
4/3πr1(cube) = πr(square)h
SO, r1(cube) = 12×12×6.75×3/4
SO, r1(cube) = 729
THEREFORE , RADIUS OF BALL = 9cm
vdm:
HOPE U UNDERSTAND BRO
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