Question

A cylindrical tub of radius 12cm contains water to a depth of 20cm. A spherical iron ball is dropped into the tub and thus the level of water is raised by 6.75cm. What is the radius of the ball?

Answer 1

$hey \: mate$

$here \: is \: your \: answer$

$question \:$


$a \: cylindrical \: tub \: of \: radius \: 12cm \: contains \: water \\ to \: a \: depth \: of \: 20cm. \: a \: spherical \: iron \: ball \: is \: \\ dropped \: into \: the \: tube \: and \: thus \: the \: level \: of \: \\ water \: is \: raised \: by \: 6.75cm. \: what \: is \: the \: radius \\ of \: the \: ball {?}$



$answer$


$radius \: of \: cylinderical \: tub \: = 12cm$
$raised \: height \: of \: water \: in \: cylindrical \: \\ tub = 6.75cm$



$suppose \: radius \: of \: sphereical \: ball = r$


$then \: volume \: of \: raised \: water \: in \: tub \: \\ = volume \: of \: ball$



$= > \: \: \pi \times (12) {}^{2} \times 6.75 = \frac{4}{3} \times \pi \times {r}^{2}$

$= > \: \: 4 \times {r}^{2} = 3 \times 144 \times 6.75$

$= > \: \: {r}^{2} = 729$

$= > \: r = 9$


Regards,

Brainly Star team