Question

a cylindrical tub of radius 12cm contains water to a depth of 25cm a spherical ball of radius 9cm is dropped into tub and the level of water raise by h cm find h

Answer 1

Solution:-

Radius of the cylinder = 12 cm

Radius of the iron ball = 9 cm

Let 'r' be the radius of the spherical iron ball.

Volume of the cylinder = volume of the spherical iron ball

πr²h = 4/3πr³

22/7*12*12*h = 4/3*22/7*9³

144*h =4/3×729

432*h = 2916

h = 6.75 cm

Answer.

Answer 2

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