Question

A cylindrical tub of radius 5 cm and length 9.8 cm is full of water. A solid in the form of a right circular cone mounted on a hemisphere is immersed in the tub. If the radius of the hemisphere is immersed in the tub. If the radius of the hemi-sphere is 3.5 cm and height of the cone outside the hemisphere is 5 cm, find the volume of the water left into hr tub.(Take π=22/7)

Answer 1

Volume of the water left into hr tub = 616.51 cm³

Given:

• A cylindrical tub of radius 5 cm and length 9.8 cm is full of water.
• A solid in the form of a right circular cone mounted on a hemisphere is immersed in the tub.
• Radius of the hemi-sphere is 3.5 cm.
• Height of the cone outside the hemisphere is 5 cm.

To find:

   Volume of the water left into hr tub.

Formula used:

• Volume of cylinder = $\pi$ × (Radius)² × Height
• Volume of hemi sphere = $\frac{2}{3}$ × $\pi$ × (Radius)³
• Volume of cone = $\frac{1}{3}$ × $\pi$ × (Radius)² × Height

Explanation:

• Initial volume of water = $\pi$ × (5)² × 9.81

                                     =770.475 cm³

• Volume of hemi sphere = $\frac{2}{3}$ × $\pi$  × (3.5)³

                                       = 89.79 cm³

• Volume of cone = $\frac{1}{3}$ × $\pi$ × (3.5)² × 5

                          = 64.14 cm³

• Volume of hemi sphere + Volume of cone = 89.79 + 64.14 =153.93 cm³

• Hence if A solid in the form of a right circular cone mounted on a hemisphere is immersed in the tub.That much of water will go outside the cylinder. then the remaining amount of water

      = 770.475- 153.93

      = 616.51 cm³

To learn more....

1 Importance of mensuration

https://brainly.in/question/8447620

2 Solve this mensuration question of class 8

https://brainly.in/question/1858405