A cylindrical tube, open at both ends, has radius 10.4cm and length 21.2cm. if thickness is 8mm everywhere find volume of the tube.
(Use, π=22/7)
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★ Given:
- A cylindrical tube open at both ends
- Radius of cylindrical tube = 10.4 cm
- Length of tube = 21.2 cm
- Thickness of tube = 8mm = 0.8cm
★ To Find:
- Volume of tube
★ Formula Used:
▪︎Volume of hollow Cylinder = πh ( (r¹)² - (r²)²)
Where;
- π = pi = 22/7
- h = Height
- r¹ = Radius¹
- r² = Radius²
★ Solution:
Here,
Radius¹ = 10.4 cm
➢ Finding Radius².
Radius²
= Radius¹ - Thickness
= 10.4 cm - 0.8 cm
= 9.6cm
➢ Finding volume of cylindrical tube.
As, cylindrical tube open at both the side
Hence, it is a hollow cylcylinder
Volume of hollow cylinder
= πh ( (r¹)² - (r²)²)
= π×21.2 ( ( 10.4 )² - ( 9.6 )²)
= π × 21.2 × (108.16 - 92.16)
= (22/7) × 21.2 × 16
= (22/7) × 339.2
= (22 × 339.2)÷7
= 7462.4 ÷ 7
= 1066.0571428...
∴ Volume of tube is 1066.06 (approx.)
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